kekon

I use Ca(NO3)2*4H2O as a source of NO3 but it seems the fertilator does not calculate NO3 properly. For example, 1g dosed per 200 liters gives above 3ppm NO3 and 0.85 ppm Ca. But when i calculated it myself it equals to 2.6 ppm NO3 and 0.85 ppm Ca. I'm not a chemist and i may be wrong but according to my calculations NO3 value is calculated incorrectly in the fertilator.

an example:

atomic masses:

Ca = 40.08
N = 14
O = 16
H = 1

Ca(NO3)2 * 4H2O = 40.08 + (14 + 16 * 3) * 2 + 4 * (1 * 2 + 16) = 236.08

(NO3)2 = 124
Ca = 40.08

So, NO3 is: (14 + 16 * 3) / 236.08 = 52.5%

When 1g Ca(NO3)2 * 4H2O is dosed per 200L it is: (1000mg * 0.52) / 200L = 2.6 ppm

But the fertilator gives more than 3ppm NO3

MiamiAG

Hi,

Not sure of the calculation but the Fertilator does have some bugs. It is one of the projects we are working on. Thanks for the note.