I think I might have figured it out on my own but need someone to double check it for me....

Apparently the equation to find grams of dry compound to use to get a specific concentration of a chamical can be found

here I did the math to find the mass percentage factor for K2CO3 (equation found

here and plugged it into the first formula. The conversion for degrees hardness to ppm is 17 ppm for 1 degree. This gives me...

17x3.77x10/[.60x1000]=1.068

So 1.07 grams of K2CO3 will raise 10gallons of water by 1 degree kH. Did I do that right?

If so, then if I want to raise my tank water by 3 degrees kH I need to add 3.21grams, correct?

am I doing the math correct in that the dosing will add 66ppm of K?