CaCl2

2341 Views 4 Replies 4 Participants Last post by bharada, Feb 19, 2005

Edward

Discussion Starter · Jun 28, 2004

Find amount of target chemical from given concentration

100 liters
Actual volume OFF
Calcium in Calcium Chloride
Desired ppm: 1
Grams of dry compound to use: 0.73

Shouldn't be the Grams of dry compound to use: 0.28 ?

http://www.ch.cam.ac.uk/magnus/MolWeight.html
CaCl2 -> Ca 36.111%, Cl 63.888%
0.28 = 10 x (1/36.1)

Thank you,
Edward

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Roger Miller

· #2 · Jun 30, 2004

More on CaCl2.

CaCl2 comes in three varieties; anhydrous, di hydrate and 6-hydrate. It makes a difference. The tech grade CaCl2 (deicer) that I have appears to be the di-hydrate.

I used my tech-grade material to work out CaCl2 dosing empirically and found that it gave 1 degree of hardness/teaspoon/50 gallons of water. That is 7 ppm Ca per teaspoon per 50 gallons of water, and it is consistent with my theoretical calculations. The fertilator says that dose should produce 0.85 ppm calcium.

Someone using the fertilator to dose CaCl2 should get a lot more calcium then they bargained for.

Roger Miller

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MiamiAG

· #3 · Aug 25, 2004

Rectified in the new version. Thanks.

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Edward

Discussion Starter · #4 · Sep 10, 2004

The fertilator is calculating 0.73g of Calcium Chloride to make 1ppm in 100 liters. This calculation is for CaCl2 10H2O, not sure where to get this.

The most available are these three,

Calcium Chloride dihydrate CaCl2 2H2O
Calcium Chloride anhydrous CaCl2
Calcium Chloride 6-hydrate CaCl2 6H2O

Each will be needed in a different quantity to achieve the same concentration of 1ppm in 100 liters:

Calcium Chloride dihydrate CaCl2 2H2O /0.367g
Calcium Chloride anhydrous CaCl2 /0.277g
Calcium Chloride 6-hydrate CaCl2 6H2O /0.547g

Members need to have the option to select the right compound in the Fertilator to get the correct result.

Thank you,
Edward

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bharada

· #5 · Feb 19, 2005

So when will the bugs regarding CaCl2 be fixed in the fertilator. It's still showing the same results for 1g vs 1tsg of CaCl2 and it still doesn't seem to correlate to values offered by Edward.

However, I'm mainly concerned with the accuracy of the calculations in the "Find percent solution of nutrient in water" since I find it easier to dose liquid solutions than dry chemicals.

Thanks.

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